2400-160f+2f^2=0

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Solution for 2400-160f+2f^2=0 equation:


Simplifying
2400 + -160f + 2f2 = 0

Solving
2400 + -160f + 2f2 = 0

Solving for variable 'f'.

Factor out the Greatest Common Factor (GCF), '2'.
2(1200 + -80f + f2) = 0

Factor a trinomial.
2((20 + -1f)(60 + -1f)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(20 + -1f)' equal to zero and attempt to solve: Simplifying 20 + -1f = 0 Solving 20 + -1f = 0 Move all terms containing f to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1f = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1f = 0 + -20 -1f = 0 + -20 Combine like terms: 0 + -20 = -20 -1f = -20 Divide each side by '-1'. f = 20 Simplifying f = 20

Subproblem 2

Set the factor '(60 + -1f)' equal to zero and attempt to solve: Simplifying 60 + -1f = 0 Solving 60 + -1f = 0 Move all terms containing f to the left, all other terms to the right. Add '-60' to each side of the equation. 60 + -60 + -1f = 0 + -60 Combine like terms: 60 + -60 = 0 0 + -1f = 0 + -60 -1f = 0 + -60 Combine like terms: 0 + -60 = -60 -1f = -60 Divide each side by '-1'. f = 60 Simplifying f = 60

Solution

f = {20, 60}

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